Posted by **Cathy** on Saturday, December 1, 2012 at 7:13am.

A circle has an area equal to 25 pi sq.cm. Its diameter AB coincides with one of the sides of triangle ACB in which the vertex C lies on the circle. If the triangle has an area equal to 11 sq.cm, find its perimeter.

Please include solution. Thanks.

- solid mensuration -
**drwls**, Saturday, December 1, 2012 at 7:59am
The circle radius is 5 cm. That comes from the area.

The triangle ACB is a right triangle with AB as a diameter. The length of AB is 10 cm, since it is a diameter

(AC)^2 + (BC)^2 = (AB)^2 = 100

Area = (1/2)(AB)*(BC) = 11

(AC)*(BC) = 22

(BC)=22/(AC)

(AC)^2 + 484/(AC)^2 = 100

Solve for AC. The short side is about 2.3. Then get BC and the perimenter.

Then get BC

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