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December 18, 2014

December 18, 2014

Posted by **Cathy** on Saturday, December 1, 2012 at 6:53am.

- solid mensuration -
**Reiny**, Saturday, December 1, 2012 at 10:01amMake your sketch

let the radius be r

r^2 = 5^2 + 7.5^2 = 81.25

r - √81.25

central angle formed by the chord:

let Ø be the angle at the centre formed by the right-angled triangle

tanØ = 5/7.5

Ø = 33.69°

central angle is 2Ø = 67.38°

area of whole circle = π(√81.25)^2 = 81.25π

so by simple ratio:

area of**sector**:

sector/84=1.25π = 67.38/360

sector = ....

area of triangle formed by the chord in that sector

= (1/2)(15)(5) = 75/2

area of**segment**= 75/2 - area of sector

I will leave the button pushing up to you

- solid mensuration -
**Glen**, Monday, December 15, 2014 at 7:30am42.35

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