Posted by Dwi on Saturday, December 1, 2012 at 5:46am.
Remember that a weight force Mg = 19.6 N is also acting on the object in the opposite direction
While being pulled up, it accelerates at a rate
a = (F-M*g)/M = (20-19.6)/2 = 0.2 m/s^2
Its final velocity at release will be
a*t = 0.8 m/s.
From that release velocity, you can compute the height that it rises after release. It will acquire additional height (about 1.6 m) while being pulled
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