Posted by **confused--two questions please help** on Saturday, December 1, 2012 at 2:07am.

find the equation of the line that is parallel to the line y=15x and contains the point (1,-4)

y=

find the distance d (p_1, and p_2) between the points p_1 and p_2

p_1=(-2,1)

p_2=(1,4)

- college algebra -
**drwls**, Saturday, December 1, 2012 at 3:22am
(1) The slope must be 15. To pass through (1,-4), it must be the equation

y + 4 = 15 (x - 1)

That can be rewritten in standard form as

y = 15x -19

(2) (distance)^2 = (y2-y1)^2 +(x2-x1)^2

=(4-1)^2 + [1 - (-3)]^2 = 9 + 16 = 25

distance = 5

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