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March 28, 2017

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find the equation of the line that is parallel to the line y=15x and contains the point (1,-4)
y=


find the distance d (p_1, and p_2) between the points p_1 and p_2
p_1=(-2,1)
p_2=(1,4)

  • college algebra - ,

    (1) The slope must be 15. To pass through (1,-4), it must be the equation
    y + 4 = 15 (x - 1)
    That can be rewritten in standard form as
    y = 15x -19

    (2) (distance)^2 = (y2-y1)^2 +(x2-x1)^2
    =(4-1)^2 + [1 - (-3)]^2 = 9 + 16 = 25
    distance = 5

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