Posted by Chris on Saturday, December 1, 2012 at 12:39am.
E is the point of intersection of AC and BD.so AC=58 ft which is AE+CE=32+26= 58.
Now we have 2 triangles ACB and ACD.
Area of triangle ACB= base.height/2
58 times12/2=348 ftsquare
Area of triangle ACD=58 times 26/2=754 square ft
To find the area of the quadrilateral ,we add the areas of two triangles which is 348+ 754= 1102 ft square
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