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April 18, 2014

April 18, 2014

Posted by **Chris** on Saturday, December 1, 2012 at 12:39am.

AE = 32 ft.

BE = 12 ft.

CE = 26 ft.

DE = 26 ft.

There is a diagram. The scale is off.

B

/|\

/ | \

/ | \

/ | \

/ | \

/ |-| \

A------E------C

\ | /

\ | /

\ | /

\ | /

\ | /

\D/

I need the formula please.

Possible answers

1102ft sq

2288ft sq

1008ft sq

2204ft sq

Thank you.

- Math 8th Grade - Ms. Sue please -
**Praphul**, Saturday, December 1, 2012 at 7:00amE is the point of intersection of AC and BD.so AC=58 ft which is AE+CE=32+26= 58.

Now we have 2 triangles ACB and ACD.

Area of triangle ACB= base.height/2

58 times12/2=348 ftsquare

Area of triangle ACD=58 times 26/2=754 square ft

To find the area of the quadrilateral ,we add the areas of two triangles which is 348+ 754= 1102 ft square

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