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March 1, 2015

March 1, 2015

Posted by **zach w** on Saturday, December 1, 2012 at 12:37am.

find intercept

a circle equation x^2+y^2+4x-4y-1=0 and graph

2)find domain and range f(x)=x^2-4x-5

find vertex of f(x) =x^2+4x-21

- math urgent urgent urgent -
**Steve**, Saturday, December 1, 2012 at 12:28pm(12,0) and (0,6)

center at (-2,2) radius 3

domain all reals, range all reals >= -9

(-2,-25)

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