Posted by LS on Friday, November 30, 2012 at 10:23pm.
Read http://www.studyphysics.ca/newnotes/20/unit03_mechanicalwaves/chp141516_waves/lesson51.htm
to convince yourswelf that the third harmonic wavelength is in this case (3/2)L, where L is the pipe length.
In this case, the wavelength is
lambda = V/f = 343/406 = 0.8448 m
The tube length must be 2/3 of that which would be 0.563 m
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