Physics HELP!!
posted by Angie on .
A loudspeaker is placed between two observers who are 113m apart, along the line connecting them. If one observer records a sound level of 51.8dB and the other records a sound level of 75.8dB, how far is the speaker from each observer?
Enter the longest distance first.

I2/I1 = (r2)^2/(r1)^2
square root of (I2/I1) = r2/r1
This will be the difference between the two.
Therefore (distance between the two people/ square root of (I2/I1)) = smallest distance from loud speaker.
And distance between the two people minus the smallest distance is the largest distance. 
Log10(I2/I1) = 1/10 (dB2  dB1)
10^[0.1(dB2dB1)] = I2/I1