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November 28, 2014

November 28, 2014

Posted by **amaa** on Friday, November 30, 2012 at 9:19pm.

tan θ = − sqrt 3/3

- precalculus -
**Reiny**, Friday, November 30, 2012 at 11:05pmtanØ = -√3/3

from the 30-60-90 triangle, you should recognize that tan 30° = 1/√3 = √3/3

or , using your calculator find tan^1 (√3/3) to get 30°

but the tangent is negative in II and Iv

so Ø = 150°

or Ø = 330°

check with your calculator, it is correct

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