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October 1, 2016
Posted by **Anonymous ** on Friday, November 30, 2012 at 8:46pm.

- Calculus -
**Count Iblis**, Friday, November 30, 2012 at 9:21pmx = 7 sinh(t)

sqrt(49 + x^2) = 7 sqrt[1 + sinh^2(t)] = 7 cosh(t)

dx = 7 cosh(t) dt

The integral is thus:

49 Integral of cosh^2(t) dt =

49 Integral of [cosh(2t) + 1]/2 dt =

49 [t/2 + 1/4 sinh(2t)]