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October 20, 2014

October 20, 2014

Posted by **Anonymous** on Friday, November 30, 2012 at 8:20pm.

- Calculus -
**Steve**, Saturday, December 1, 2012 at 12:20amsin^2(8x)cos^2(8x)

= 1/4 (2sin(8x)cos(8x))^2

= 1/4 sin^2(16x)

now use integration by parts twice to evaluate.

- Calculus -
**Steve**, Saturday, December 1, 2012 at 12:21amor, even easier, recall your half-angle formula to show that this is

1/2 (1-cos(32x))

- Calculus -
**Anonymous**, Saturday, December 1, 2012 at 12:33amIf i use integration by parts can i take out 1/4 from the integral and make u=sin^2(16x) and dv=dx ?

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