There are two adults and three children (under the age of 12). They qualify for a special family rate of $174.45. The clerk tells them that a child's ticket always costs $11 less than an adult's ticket. How much is each adult ticket and how much is each child's ticket?
Write an expression to represent the cost of the child's ticket in terms of the adult ticket. Remember the child's ticket is $11 less than the adult's ticket.
I think this was the same question.
Why are you posting it again?
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The Total of all 5 individual to a family plan is $ 174.45
Now let divide total by the number of the individual (5)
174.45/5 = 34.89
let have
34.89 for each individual.
Than we say children pay 11 $ less than adults
so means
(34.89 - 11)* 3 = 23.89 * 3= 71.67
we have several ways to solve the problem now that we now the kids Total coast was 71.67
We can either take the whole amount 174.45 - 71.67 =
or we can take
(3*11) = 33
Divide by the number of adults
33/2
16.5
which means we need to give or add to each adults 16.5 plus their 34.39
that will make the total of 51.39 per adults.
Now 51.39 * 2 = $ 102.78
let us sum up to know if it is correct
Adult ( 2) = $ 102.78
Children (3) = $ 71.67
The Total is = $174.45
To find the cost of each adult ticket and each child's ticket, we can use algebraic expressions.
Let's represent the cost of each adult ticket as 'A' and the cost of each child's ticket as 'C'.
According to the information given, the child's ticket always costs $11 less than the adult's ticket.
So, the expression representing the cost of the child's ticket in terms of the adult ticket would be:
C = A - 11
Using this expression, we can now solve the problem.