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Posted by **Nate** on Friday, November 30, 2012 at 6:26pm.

lim

x->2

(2x^2 +1)/(x^2 + 6x -4)

- Calculus -
**Reiny**, Friday, November 30, 2012 at 6:31pmstep 1 in any limit question is to actually substitute the approach value into your expression.

If you get a real number, that is your answer, you are done!

lim (2x^2 + 1)/(x^2 + 6x - 4) as x --> 2

= 9/12

= 3/4

Voila!!! all done.

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