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January 26, 2015

January 26, 2015

Posted by **Ali** on Friday, November 30, 2012 at 5:43pm.

x=0 x=1 y=0 y=4+x^5

- Calculus [Finding volume of solid] -
**Reiny**, Friday, November 30, 2012 at 6:23pmV = π∫(4+x^2)^2 dx from 0 to 1

= π∫(16 + 8x^5 + x^10) dx from 0 to 1

= π [ 16x + (4/3)x^6 + (1/11)x^11 ] from 0 to 1

= π [ 16 + 4/3 + 1/11 - 0]

= 575π/33

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