Posted by Ali on Friday, November 30, 2012 at 5:43pm.
V = π∫(4+x^2)^2 dx from 0 to 1
= π∫(16 + 8x^5 + x^10) dx from 0 to 1
= π [ 16x + (4/3)x^6 + (1/11)x^11 ] from 0 to 1
= π [ 16 + 4/3 + 1/11 - 0]
= 575π/33
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