Calculus [rotation of region bounded by curves]
posted by Ali on .
Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis.
y=3x^2, x=1, y=0 about the x-axis
volume = π∫(3x^2)^2 dx from x - 0 to x=1
= π∫9x^4 dx from 0 to 1
= π [ (9/5)x^5 ] from 0 to 1
= π(9/5 - 0)