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Posted by Frank on Friday, November 30, 2012 at 2:18pm.

integrate from 0 to pi/2 (3sinxcosx)/(1+3sin^2x)^1/2

note that if u = 1+3sin^2x du = 6sinxcosx so you have ∫[1,4] u^(-1/2) 1/2 du = √u [1,4] = 1

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