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December 22, 2014

December 22, 2014

Posted by **Frank** on Friday, November 30, 2012 at 2:18pm.

- Calc 1 -
**Steve**, Friday, November 30, 2012 at 2:28pmnote that if

u = 1+3sin^2x

du = 6sinxcosx

so you have

∫[1,4] u^(-1/2) 1/2 du

= √u [1,4]

= 1

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