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Calc 1

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integrate from 0 to pi/2 (3sinxcosx)/(1+3sin^2x)^1/2

  • Calc 1 - ,

    note that if
    u = 1+3sin^2x
    du = 6sinxcosx

    so you have

    ∫[1,4] u^(-1/2) 1/2 du
    = √u [1,4]
    = 1

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