Rball = .07 meter
KE = (1/2) m v^2 + (1/2)I w^2
I = (2/5) m r^2
v = w Rball = .07 w
Ke = (1/2) m (.07 w)^2 + (2/5) m .07^2 w^2
= m (9/10) (.0049) w^2 = .00441 m w^2
Change in Pe down ramp = m g h = m(9.81)(.57) = .55917 m
Ke = change in Pe
.55917 m = .00441 m w^2
w^2 = 127
w = 11.3 radians/second
v = w r = .07*11.3 = .788 meters/second horizontal speed
Now how long to fall the last 1.38 meters?
1.38 = (1/2) g t^2
t^2 = .281
t = .53 seconds in the air
how far in .53 seconds at .788 m/s
x = v t = .788 * .53 = .418 meters
radians/second = 11.3
for .53 seconds = 5.99 radians
5.99/2 pi = .953 revolutions
CHECK MY ARITHMETIC
Answer this Question
Physics please help!! - A 1.94 kg solid sphere (radius = 0.105 m) is released ...
physics - A thin spherical shell of mass M = 2.00 kg is released from rest at ...
PHYSICS - A 20.0 kg solid cylinder, 0.25m in radius, and a 5.0 kg thin hollow ...
Physics - Box, mass m 1 , at rest against a compressed spring, spring constant k...
Physics-please help - You're given a ramp 0.5m in height with a 3m incline. A ...
physics - A ball rolls up a ramp which abruptly ends with the ramp dropping ...
physics - A uniform solid sphere of mass M and radius R is rolling without ...
Physics - A uniform solid sphere of mass M and radius R is rolling without ...
Physics Help.. - A small cube (m=0.290 kg) is at a height of 261 cm up a ...
physics - Hi, ive been trying to get this problem for a couple of days now but i...