Posted by **michelle** on Friday, November 30, 2012 at 12:16pm.

A hydraulic brake system is shown. The

area of the piston in the master cylinder is 6.32 cm^2, and the area of the piston in the brake cylinder is 1.83 cm^2. The coeﬃcient of kinetic friction between the brake shoe and the wheel drum is 0.443.

How large is the frictional force between the brake shoe and the wheel drum when a force of 49 N is exerted on the pedal? Answer in units of N.

- physics -
**Elena**, Friday, November 30, 2012 at 12:36pm
Pascal’s principle F1/A1=F2/A2.

F(bc)={A(bc)/A(mc)}•F(pedal) =

=(1.83/6.32) •49 =14.2 N

This is the normal force exerted on the brake shoe.

The frictional force is

F(fr) =μ F(bc)=0.442•14.2 =6.3 N

- physics -
**michelle**, Friday, November 30, 2012 at 12:41pm
Wow thank you so much! This problem has been bothering me for a week now

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