Posted by **Joanna** on Friday, November 30, 2012 at 12:06pm.

invests 7000 for 1 year part at 5% part at 11% and the remainder at 13% total amount of income from these investments was $774. The amount of money invested at 13% was $1200 more than the amounts invested at 5% and 11% combined find the amount invested at each rate

- Precalculus -
**Steve**, Friday, November 30, 2012 at 12:50pm
if x at 5%, y at 11% and z at 13%,

x+y+z = 7000

.05x + .11y + .13z = 774.00

z = 1200+x+y

(x,y,z) = (1300,1600,4100)

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