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January 29, 2015

January 29, 2015

Posted by **Joanna** on Friday, November 30, 2012 at 12:06pm.

- Precalculus -
**Steve**, Friday, November 30, 2012 at 12:50pmif x at 5%, y at 11% and z at 13%,

x+y+z = 7000

.05x + .11y + .13z = 774.00

z = 1200+x+y

(x,y,z) = (1300,1600,4100)

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