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December 18, 2014

December 18, 2014

Posted by **Kasie** on Friday, November 30, 2012 at 11:17am.

F'(x) = f(b)-f(a) / b-a

f(x)=x^2-8x+3; interval [-1,6]

- AP CALCULUS -
**Steve**, Friday, November 30, 2012 at 11:38amI assume you want to find c such that f'(c) = (f(6)-f(-1))/7

nothing simpler:

f'(x) = 2x-8

f(6) = -9

f(-1) = 12

so, we want f'(c) = -21/7 = -3

2x-8 = -3

x = 5/2

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