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March 26, 2017

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Using the mean value theorem;
F'(x) = f(b)-f(a) / b-a

f(x)=x^2-8x+3; interval [-1,6]

  • AP CALCULUS - ,

    I assume you want to find c such that f'(c) = (f(6)-f(-1))/7

    nothing simpler:

    f'(x) = 2x-8
    f(6) = -9
    f(-1) = 12

    so, we want f'(c) = -21/7 = -3
    2x-8 = -3
    x = 5/2

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