Posted by Anonymous on .
Part A:
A cardinal (Richmondena cardinalis) of mass 4.50×10^−2 kg and a baseball of mass 0.142 kg have the same kinetic energy. What is the ratio of the cardinal's magnitude p(c) of momentum to the magnitude p(b) of the baseball's momentum?
Part B:
A man weighing 650 N and a woman weighing 460 N have the same momentum. What is the ratio of the man's kinetic energy K(m) to that of the woman K(w)?

PHYSICS  PLEASE HELP 
Elena,
(A)
KE₁=m₁v₁²/2= (m₁v₁)²/2 m₁=p₁²/2m₁
KE₂=m₂v₂²/2= (m₂v₂)²/2 m₂= p₂²/2m₂
KE₁=KE₂
p₁²/2m₁=p₂²/2m₂
p₁²/p₂²=m₁/m₂
p₁/p₂=sqrt(m₁/m₂)
(B)
KE₁= p₁²/2m₁
KE₂= p₂²/2m₂
KE₁/KE₂=m₂/m₁