Friday

April 25, 2014

April 25, 2014

Posted by **Mike** on Friday, November 30, 2012 at 10:48am.

- calculus -
**Steve**, Friday, November 30, 2012 at 10:58amat a depth of h ft, the radius of the water surface is r=(12/23)*h ft

v = 1/3 pi r^2 h

= pi/3 * (12/23)^2 * h^3

dv/dt = pi(12/23)^2 h^2 dh/dt

20 = pi(12/23)^2 (17)^2 dh/dt

dh/dt = 2645 / 10404pi = 0.081 ft/min = 0.97 in/min

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