If saturated solution of barium chloride at 30 degree Celsius contains 150g water how much additional barium chloride can be dissolved by heating it to 60 degree Celsius?
30 degrees Celsius = 38.2
60 degrees Celsius = 46.6
30 degrees Celsius = 38.2 (what/what)
60 degrees Celsius = 46.6 (what/what)
That is is that 38.2 g BaCl2/100 mL soln? or 150 mL soln? or some other value?
69.3 additional BaCl2
To determine how much additional barium chloride can be dissolved by heating the solution from 30 degrees Celsius to 60 degrees Celsius, we need to calculate the difference in solubility between the two temperatures.
The solubility of a substance generally increases with temperature, meaning more of the substance can dissolve as the temperature rises. In this case, we are given the solubility at 30 degrees Celsius (38.2 g/100g water) and 60 degrees Celsius (46.6 g/100g water).
To find the difference in solubility, subtract the solubility at 30 degrees Celsius from the solubility at 60 degrees Celsius:
46.6 g/100g water - 38.2 g/100g water = 8.4 g/100g water
This means that for every 100 grams of water, an additional 8.4 grams of barium chloride can dissolve when the temperature is increased from 30 to 60 degrees Celsius.
Since we have 150 grams of water in the saturated solution, we can calculate the additional amount of barium chloride that can be dissolved by multiplying the difference in solubility by the amount of water in the solution:
8.4 g/100g water * 150 g water = 12.6 grams
Therefore, an additional 12.6 grams of barium chloride can be dissolved by heating the solution from 30 degrees Celsius to 60 degrees Celsius.