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Posted by on Thursday, November 29, 2012 at 11:29pm.

A block initially at rest is allowed to slide
down a frictionless ramp and attains a speed
v at the bottom.
To achieve a speed 3.9 v at the bottom, how
many times as high
h2
h1
must a new ramp be?

  • physics - , Friday, November 30, 2012 at 3:13am

    mgh₁=mv₁²/2
    mgh₂=mv₂²/2= m(3.9v₁)²/2=15.21 mv₁²/2
    h₂=15.21h₁

  • physics - , Thursday, January 28, 2016 at 9:02pm

    no idea

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