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September 2, 2014

September 2, 2014

Posted by **Alex** on Thursday, November 29, 2012 at 11:28pm.

Can someone help & explain how to solve this question? Please.

- Math (Calculus) -
**Steve**, Friday, November 30, 2012 at 12:10amv = 4/3 pi r^3

dv/dt = 4pi r^2 dr/dt

= 4pi * 25cm^2 * -0.3cm/min

= -30pi cm^3/min

- Math (Calculus) -
**Reiny**, Friday, November 30, 2012 at 10:45amsmall correction to Steve's solution

d(diameter)/dt = -.3

dr/dt = -.15

so dv/dt = 4π(25)(-.15) = -15π cm^3/min

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