Monday

January 26, 2015

January 26, 2015

Posted by **Alex** on Thursday, November 29, 2012 at 11:28pm.

Can someone help & explain how to solve this question? Please.

- Math (Calculus) -
**Steve**, Friday, November 30, 2012 at 12:10amv = 4/3 pi r^3

dv/dt = 4pi r^2 dr/dt

= 4pi * 25cm^2 * -0.3cm/min

= -30pi cm^3/min

- Math (Calculus) -
**Reiny**, Friday, November 30, 2012 at 10:45amsmall correction to Steve's solution

d(diameter)/dt = -.3

dr/dt = -.15

so dv/dt = 4π(25)(-.15) = -15π cm^3/min

**Answer this Question**

**Related Questions**

calculus - A spherical snowball is melting in such a way that its diameter is ...

Calculus - A spherical snowball is melting in such a way that its diameter is ...

MATH - A spherical snowball is melting in such a way that its diameter is ...

math - A spherical snowball is melting in such a way that its diameter is ...

Math! - A spherical snowball is melting in such a way that its diameter is ...

related rates - A spherical snowball is melting in such a way that its diameter ...

CAL - (1 pt) A spherical snowball is melting in such a way that its diameter is ...

calc - A spherical snowball is melting in such a way that its diameter is ...

Calc - A spherical snowball is melting in such a way that its diameter is ...

Calculus - A spherical snowball is melting so that its diameter is decreasing at...