Posted by Brittany Penman on Thursday, November 29, 2012 at 11:14pm.
Suppose that a polynomial function of degree 5 with rational coefficients has the given numbers as zeros. Find the other zero( s):
1, radical 3, 11/3

PreCalculus  Steve, Friday, November 30, 2012 at 12:20am
(x+1)(x√3)(x+√3)(3x11)
no way to tell the 5th root.

PreCalculus  Reiny, Friday, November 30, 2012 at 8:21am
One of the rational roots would have to be a double root, so it could be
y = (x+1)^2(x√3)(x+√3)(3x11) = (x+1)^2(x^2+9)(3x11)
or
y = (x+1)(x√3)(x+√3)(3x11)^2 = (x+1)(x^2+9)(3x11)^2

PreCalculus  Steve, Friday, November 30, 2012 at 10:30am
did I miss an i somewhere?
(x√3)(x+√3) = x^23

PreCalculus  jennifer, Saturday, May 4, 2013 at 7:26pm
Suppose that a polynomial function of degree 5 with rational coefficients has 2, 5, and 3  I as zeros. Find the other zeros.
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