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July 25, 2014

July 25, 2014

Posted by **Brittany Penman** on Thursday, November 29, 2012 at 11:14pm.

-1, radical 3, 11/3

- PreCalculus -
**Steve**, Friday, November 30, 2012 at 12:20am(x+1)(x-√3)(x+√3)(3x-11)

no way to tell the 5th root.

- PreCalculus -
**Reiny**, Friday, November 30, 2012 at 8:21amOne of the rational roots would have to be a double root, so it could be

y = (x+1)^2(x-√3)(x+√3)(3x-11) = (x+1)^2(x^2+9)(3x-11)

or

y = (x+1)(x-√3)(x+√3)(3x-11)^2 = (x+1)(x^2+9)(3x-11)^2

- PreCalculus -
**Steve**, Friday, November 30, 2012 at 10:30amdid I miss an i somewhere?

(x-√3)(x+√3) = x^2-3

- PreCalculus -
**jennifer**, Saturday, May 4, 2013 at 7:26pmSuppose that a polynomial function of degree 5 with rational coefficients has -2, 5, and 3 - I as zeros. Find the other zeros.

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