PreCalculus
posted by Brittany Penman on .
Suppose that a polynomial function of degree 5 with rational coefficients has the given numbers as zeros. Find the other zero( s):
1, radical 3, 11/3

(x+1)(x√3)(x+√3)(3x11)
no way to tell the 5th root. 
One of the rational roots would have to be a double root, so it could be
y = (x+1)^2(x√3)(x+√3)(3x11) = (x+1)^2(x^2+9)(3x11)
or
y = (x+1)(x√3)(x+√3)(3x11)^2 = (x+1)(x^2+9)(3x11)^2 
did I miss an i somewhere?
(x√3)(x+√3) = x^23 
Suppose that a polynomial function of degree 5 with rational coefficients has 2, 5, and 3  I as zeros. Find the other zeros.