Posted by **Will** on Thursday, November 29, 2012 at 9:59pm.

what is the equation for the perpendicular bisector of the line segment whose endpoints are (-7,2) (-1,-6)

- Math -
**julia**, Thursday, November 29, 2012 at 10:35pm
The formula is y-y1= m*(x-x1)

1. Find the midpoint= [(x1-x2)/2, (y1-y2)/2]

you will get (-4,-2)

2. Find slope m1= [2-(-6)]/[-7-(-1)]= 8/-6=-4/3

3. find the slope of the perpendicular line

m1*m2=-1

-4/3*m2= -1

m2= 3/4

4. Plug in given points (-7,2) and (-1,-6) and m2 in the formula that I wrote in the beginning

y-(-2)=3/4(x-(-4))

y+2=3/4(x+4)

y+2=3/4x+3

y=3/4x+1 this is the equation your were looking for.

Please, make sure the numbers are correct and double check the math (in case of typo), but the actual idea is correct.

- Math -
**roberto**, Monday, November 17, 2014 at 10:19am
Indicate the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5).

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