An artist makes a painting that is 12 feet by 9 feet. He paints a frame around the painting. The frame is 4 inches wide. What is the perimeter of the outside edge of the frame?

P = 2L + 2W

P = 2(12 1/3) + 2(9 1/3)

P = ?

To find the perimeter of the outside edge of the frame, we first need to calculate the dimensions of the painting with the frame included.

Given:
Length of the painting = 12 feet
Width of the painting = 9 feet
Width of the frame = 4 inches

We need to convert the width of the frame from inches to feet, since the dimensions of the painting are in feet. There are 12 inches in a foot, so 4 inches is equal to 4/12 = 1/3 feet.

Now, let's calculate the dimensions of the painting with the frame included:
Length of the painting with frame = length of the painting + 2 * width of the frame
Width of the painting with frame = width of the painting + 2 * width of the frame

Length of the painting with frame = 12 feet + 2 * (1/3 feet) = 12 feet + 2/3 feet = (12 + 2/3) feet
Width of the painting with frame = 9 feet + 2 * (1/3 feet) = 9 feet + 2/3 feet = (9 + 2/3) feet

Now that we have the dimensions of the painting with the frame included (12 2/3 feet by 9 2/3 feet), we can calculate the perimeter of the outside edge of the frame.

Perimeter of the outside edge of the frame = 2 * (length of the painting with frame + width of the painting with frame)
Perimeter of the outside edge of the frame = 2 * ((12 2/3) feet + (9 2/3) feet)
Perimeter of the outside edge of the frame = 2 * (22/3 feet + 29/3 feet)
Perimeter of the outside edge of the frame = 2 * (51/3 feet)
Perimeter of the outside edge of the frame = 2 * (17 feet)
Perimeter of the outside edge of the frame = 34 feet

Therefore, the perimeter of the outside edge of the frame is 34 feet.