bullet traveling 8.o*10^2 (800) meters per second horizontally hits a target 180 m away. how far does the bullet fall before it hits the target?
4.9*10^3
To find how far the bullet falls before hitting the target, we need to calculate the vertical distance covered by the bullet during its horizontal travel.
First, we need to determine the time it takes for the bullet to reach the target. To do that, we can use the horizontal distance traveled by the bullet and its horizontal velocity.
We know that the horizontal velocity of the bullet is 800 m/s, and the horizontal distance to the target is 180 m.
Using the formula distance = velocity × time, we can rearrange it to solve for time: time = distance / velocity.
time = 180 m / 800 m/s = 0.225 seconds.
Now we need to find the vertical distance the bullet falls during this time.
The vertical distance covered by an object in free fall can be determined using the equation d = 0.5 × g × t^2, where:
d = vertical distance
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time
Plugging in the values, we get:
d = 0.5 × 9.8 m/s^2 × (0.225 s)^2
Simplifying further:
d = 0.5 × 9.8 m/s^2 × 0.050625 s^2
d ≈ 0.248 m
Therefore, the bullet falls approximately 0.248 meters (or 24.8 centimeters) before hitting the target.