Posted by Lindsay on Thursday, November 29, 2012 at 7:33pm.
SA is the rectangular base + 2ends + 2trapezpoids
for the length of the slanted base we need to use Pythagoras
H^2 = 32^2 + 3^2
h = √1033
area of base = 12√1033
area of each trapezoid
= 32(1+4)/2 = 80
short end = 12
deep end = 48
Total surface area = 12√1033 + 2(80) + 12 + 48
= 605.684 m^2
b) I will assume you meant $5 per square metre
cost = 5(above surface area)
c) I will consider one of the traps as the base
Volume = 80(12) = 960 m^3
= 960 000 litres
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