posted by Sammyjoo on .
Rename each repeating decimal as a fractio in lowest terms. Use Let statement, an equation, a proper solution (using Properties of Equality).
.5406 = 5406/10000
count the number of zeros in the denominator, and count the number of digits past the decimals, they are the same
= 2703/5000 ---- divided top and bottom by 2 to reduce , 2 being the HCF
do the others the same
careful in #3
3.274 = 3274/1000 ---- again, notice the number of zeros on the bottom match the number of decimals in the original
Sorry I repeated these question to you because I forgot to add there are repeating numbers or ellipsis.