Math
posted by Sammyjoo .
Rename each repeating decimal as a fractio in lowest terms. Use Let statement, an equation, a proper solution (using Properties of Equality).
1) 0.87
2) 0.5406
3) 0.048
4) 3.274

2.
.5406 = 5406/10000
count the number of zeros in the denominator, and count the number of digits past the decimals, they are the same
5406/10000
= 2703/5000  divided top and bottom by 2 to reduce , 2 being the HCF
do the others the same
careful in #3
3.
3.274 = 3274/1000  again, notice the number of zeros on the bottom match the number of decimals in the original
= ..... 
Sorry I repeated these question to you because I forgot to add there are repeating numbers or ellipsis.