a tennis ball is dropped from the top of 12.2 m tall building.

b) how long does it take for the ball to hit he ground?

c) what is the velocity of the ball the split second before it hits the ground?

80

To answer these questions, we can use the equations of motion and the principles of kinematics.

b) To determine the time it takes for the ball to hit the ground, we can use the equation for displacement in the vertical direction:

s = ut + (1/2)gt^2,

where:
s is the displacement (12.2 m, in this case),
u is the initial velocity (0 m/s, as the ball is dropped),
g is the acceleration due to gravity (-9.8 m/s^2),
and t is the time taken.

Rearranging the equation, we get:

s = (1/2)gt^2,
2s = gt^2,
t^2 = 2s/g,
t = sqrt(2s / g).

Substituting the given value 12.2 m for s and -9.8 m/s^2 for g, we can calculate the time it takes for the ball to hit the ground.

c) To find the velocity of the ball just before it hits the ground, we can use the equation:

v = u + gt,

where:
v is the final velocity,
u is the initial velocity (0 m/s),
g is the acceleration due to gravity (-9.8 m/s^2),
and t is the time taken (calculated from part b).

By substituting the values, we can calculate the velocity of the ball just before it hits the ground.