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September 20, 2014

September 20, 2014

Posted by **asdf** on Thursday, November 29, 2012 at 5:04pm.

I can use the anti-derivatives to get

y = 2x^3 + Cx + D

but I don't know how to get C even though I know D = 1.

- calculus -
**Steve**, Thursday, November 29, 2012 at 5:08pmyou know that

y' = 6x + C

and that y'(0) = 0, so

0 = C

y = 2x^3 + 1

- calculus -
**asdf**, Thursday, November 29, 2012 at 5:56pmSo y'(0) = 0 because there is a horizontal tangent at x = 0?

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