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August 1, 2014

August 1, 2014

Posted by **Victoria** on Thursday, November 29, 2012 at 4:46pm.

Write an equation for the line in point/slope form and slope/intercept form that has the given condition.

1. Passes through (3, 2) and is parallel to 2x-y=4

= 4x+y

2. Passes through (-1, -1) and is perpendicular to y = 5/2x + 3

=6\7x-2

- Algebra2 -
**Steve**, Thursday, November 29, 2012 at 4:50pmI can't interpret your answers.

1.

2x-y=4, or

y = 2x-4

has slope 2. So, the line through (3,2) with slope=2 is

y-2 = 2(x-3)

y = 2x-4

2.

y = 5/2 x + 3

has slope 5/2

so, the perpendicular line has slope -2/5

y+1 = -2/5 (x+1)

y = -2/5 x - 7/5

I'd be interested to know what steps you followed to arrive at your answers.

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