Posted by Garcia on Thursday, November 29, 2012 at 1:05pm.
I just took a brief look; where is the 1392 for second ionization potential? I don't see that in your calculation.
Where would I add that in to my calculation? Like would it look like this:
-Lattice energy of MX2=-891-(141+88.5+605+1392-678)
Yes, that should do it.
Also, I wonder about taking 1/2 x 177. If you do Cl2 bond dissociation for say NaCl, then you take 1/2 Bond energy because you're using only 1/2 of it to make Cl^-. But in this case you're using both parts of the X2 bond energy to make 2X^-. You multiplied 2 x electron affinity (and that is proper).
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