12 volts is applied across a 4 ohm resistor. How much power is dissipated by the resistor?

P = E^2/R = 144/4 = 36 W

To find the power dissipated by a resistor, you can use the formula:

Power (P) = (Voltage (V))^2 / Resistance (R)

In this case, the voltage (V) is 12 volts and the resistance (R) is 4 ohms. Plugging these values into the formula, we get:

P = (12 volts)^2 / 4 ohms
P = 144 volts^2 / 4 ohms
P = 36 watts

Therefore, the power dissipated by the resistor is 36 watts.

To calculate the power dissipated by a resistor, we can use the formula P = (V^2)/R, where P is the power, V is the voltage, and R is the resistance.

In this case, the voltage across the resistor is 12 volts and the resistance is 4 ohms. Plugging these values into the formula, we have:

P = (12^2) / 4

P = 144 / 4

P = 36 Watts

Therefore, the power dissipated by the resistor is 36 Watts.