Posted by kchik on Thursday, November 29, 2012 at 6:27am.
Form three students --- x
form five students ---- y
form six students ----- 100-x-y
80x + 120y + 160(100-x-y) = 10000
80x + 120y + 16000-160x-160y = 10000
-80x - 40y = -6000
2x + y = 150
but it said:
x = 2y
2(2y) + y = 150
y = 30
x = 2y = 60
remaining students = 100-30-60 = 10
I did not use matrices on such a simple problem because solving it was so much easier using the above method,
but.... if you have to use matrices
our two equations are:
2x + y = 150
x - 2y = 0
2 1 150
1 -2 0 ---->
4 2 300
1 -2 0 --->
1 -2 0
4 2 300 ---> add
1 -2 0
5 0 300
1 -2 0
1 0 60
from the last x=60
in 1st: 60-2y=0
-2y=-60
y=30
etc
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