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Posted by on Thursday, November 29, 2012 at 1:56am.

For the following equilibrium; Br2 (g) + Cl2 (g) ⇄ 2BrCl (g)

the Kc = 7.00 at 127oC. If 0.450 mol of Br2 (g) and 0.450 mol of Cl2 (g) are introduced into a 3.00 L container at 400 K, what will the equilibrium concentration of BrCl(g) be?

  • Chemisty - , Thursday, November 29, 2012 at 5:11pm

    I assume you want the concns at 127 C.

    M = mols/L = 0.450/3 = 0.150M
    ............Br2 + Cl2 ==> 2BrCl
    I.........0.150..0.150......0
    C............x.....-x......2x
    E......0.150-x...0.150-x....2x

    Substitute into Kc expression and solve for x and 2x.

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