Posted by bryan on Thursday, November 29, 2012 at 12:24am.
I assume you are studying vectors.
Draw a line at 28° of length 200 (your resultant)
Draw a line at 38° of length 207, join its tail to the first line.
That smaller line will be the vector representing the wind
I see a triangle with sides 200 and 207, with a contained angle of 10°
Let the length of the smaller side be x
by cosine law:
x^2 = 200^2 + 207^2 - 2(200)(207)cos10°
etc.
x will be you speed of the wind, and from your diagram it should be straightforward to find the wind direction
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