I understand how to multiply a polynomial by a monomial for example
6pq(3p^2+4q)= 18p^3q+24pq^2
but i don't know how to do problems like this
5(2s-1)+3=3(3s+2)
HELP PLEASE!!
5(2s-1)+3=3(3s+2)
10s - 5 + 3 = 9s + 6
s = 6 + 5 - 3
s = 8
how did you get the 's' by its self?
Did you take 9 and subtract it by 10 to get 1s but you just dropped the 1 because a variable always has and invisible 1?
Yes. I subtracted 9s from both sides.
Ohhh kayy thanks i didn't see at first... Thank You!!
You're welcome. :-)
just to be sure did i do this right?
3(3u+2)+5=2(2u-2)
9u+6+5=4u-4
5u=-15
5/5=-15/5
u=-3
Right.
To solve the equation 5(2s-1)+3=3(3s+2), let's break it down step by step:
1. Distribute the 5 to both terms inside the parentheses on the left side of the equation:
5(2s-1) + 3 = 3(3s+2)
10s - 5 + 3 = 9s + 6
2. Combine like terms on the left side:
10s - 2 = 9s + 6
3. Move all the terms containing s to one side of the equation by subtracting 9s from both sides:
10s - 9s - 2 = 9s - 9s + 6
s - 2 = 6
4. Move the constant term to the other side by adding 2 to both sides:
s - 2 + 2 = 6 + 2
s = 8
So, the solution to the equation 5(2s-1)+3=3(3s+2) is s = 8.
To check your answer, substitute s = 8 back into the original equation and see if both sides are equal:
5(2(8)-1)+3 = 3(3(8)+2)
5(16-1)+3 = 3(24+2)
5(15)+3 = 3(26)
75 + 3 = 78
78 = 78
Since both sides of the equation are equal, the solution is correct.