Posted by **Kai** on Wednesday, November 28, 2012 at 8:56pm.

An investment of $37,000 was made by a business club. The investment was split into three parts and lasted for one year. The first part of the investment earned 8% interest, the second 6%, and the the third 9%. Total interest from the investments was $3030. The interest from the first investment was 6 times the interest from the second. Find the amounts of the three parts of the investment.

- Precalc -
**Reiny**, Wednesday, November 28, 2012 at 10:02pm
amount invested at 8% --- x

amount invested at 6% --- y

amount invested at 9% ---- 37000-x-y

.08x + .06y + .09(37000-x-y) = 3030

times 100

8x + 6y + 9(37000-x-y) = 303000

-x - 3y = -30000

x + 3y = 30000 (#1)

also .08x = 6(.06)y

8x = 36y

2x = 9y

x = 9y/2 (#2)

sub into #1

9y/2 + 3y = 30000

times 2

9y + 6y = 60000

y = 4000

then x = 9(4000)/2 = 18000

and 37000-4000-18000 = 15000

$18000 at 8%

$4000 at 6%

$15000 at 9%

- Precalc -
**Kai**, Thursday, November 29, 2012 at 12:17pm
Got it before I saw this xD thanks

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