Saturday

January 24, 2015

January 24, 2015

Posted by **Kai** on Wednesday, November 28, 2012 at 8:56pm.

- Precalc -
**Reiny**, Wednesday, November 28, 2012 at 10:02pmamount invested at 8% --- x

amount invested at 6% --- y

amount invested at 9% ---- 37000-x-y

.08x + .06y + .09(37000-x-y) = 3030

times 100

8x + 6y + 9(37000-x-y) = 303000

-x - 3y = -30000

x + 3y = 30000 (#1)

also .08x = 6(.06)y

8x = 36y

2x = 9y

x = 9y/2 (#2)

sub into #1

9y/2 + 3y = 30000

times 2

9y + 6y = 60000

y = 4000

then x = 9(4000)/2 = 18000

and 37000-4000-18000 = 15000

$18000 at 8%

$4000 at 6%

$15000 at 9%

- Precalc -
**Kai**, Thursday, November 29, 2012 at 12:17pmGot it before I saw this xD thanks

**Answer this Question**

**Related Questions**

COLLEGE ALGEBRA - An investment of $63,000 was made by a business club. The ...

COLLEGE ALGEBRA - An investment of $63,000 was made by a business club. The ...

ALGEBRA - An investment of $93,000 was made by a business club. the investment ...

word problem - An investment of $93,000 was made by a business club. the ...

Algebra - an investment of 72,000 was made by a business club. the investment ...

college alg HELP! - I cannot figure a way to do this problem: An investment of $...

college alg help! - cannot figure a way to do this problem: An investment of $...

algebra - an investment of $50,000 was made by a busines club. the investment ...

Algebra investment - An investor had a total of 25,000 put into a portfolio of ...

math - An investment adviser invested $14,000 in two accounts. One investment ...