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Posted by on Wednesday, November 28, 2012 at 8:56pm.

An investment of $37,000 was made by a business club. The investment was split into three parts and lasted for one year. The first part of the investment earned 8% interest, the second 6%, and the the third 9%. Total interest from the investments was $3030. The interest from the first investment was 6 times the interest from the second. Find the amounts of the three parts of the investment.

  • Precalc - , Wednesday, November 28, 2012 at 10:02pm

    amount invested at 8% --- x
    amount invested at 6% --- y
    amount invested at 9% ---- 37000-x-y

    .08x + .06y + .09(37000-x-y) = 3030
    times 100
    8x + 6y + 9(37000-x-y) = 303000
    -x - 3y = -30000
    x + 3y = 30000 (#1)

    also .08x = 6(.06)y
    8x = 36y
    2x = 9y
    x = 9y/2 (#2)

    sub into #1
    9y/2 + 3y = 30000
    times 2
    9y + 6y = 60000
    y = 4000
    then x = 9(4000)/2 = 18000
    and 37000-4000-18000 = 15000

    $18000 at 8%
    $4000 at 6%
    $15000 at 9%

  • Precalc - , Thursday, November 29, 2012 at 12:17pm

    Got it before I saw this xD thanks

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