The binding energy of electrons in a metal is 194 kJ/mol.

Find the threshold frequency of the metal.

-----------------

The heat of fusion of ice is 6.00 kJ/mol.

Find the number of photons of wavelength = 6.78×10^−6 m that must be absorbed to melt 6.80 g of ice.

To find the threshold frequency of the metal, we can use the equation:

Binding energy of electrons = threshold frequency × Planck's constant

The binding energy of electrons in a metal is given as 194 kJ/mol.

Let's convert this to joules per particle:

1 kJ/mol = 1 kJ / (6.022 × 10^23 particles)

194 kJ/mol = 194 kJ / (6.022 × 10^23 particles)

Now, let's convert this to joules per electron:

1 particle → 1 electron

194 kJ / (6.022 × 10^23 particles) = 194 kJ / (6.022 × 10^23 electrons)

Next, we need to convert the binding energy from joules to electron volts (eV) since threshold frequencies are typically given in eV:

1 eV = 1.602 × 10^−19 J

Thus, we have:

194 kJ / (6.022 × 10^23 electrons) = (194 × 10^3 J) / (6.022 × 10^23 electrons) = (194 × 10^3 J) / (6.022 × 10^23 electrons) × (1 eV / 1.602 × 10^−19 J)

Now, divide the obtained value by the Planck's constant (h) to get the threshold frequency:

threshold frequency = ((194 × 10^3 J) / (6.022 × 10^23 electrons) × (1 eV / 1.602 × 10^−19 J)) / h

Planck's constant (h) is approximately 6.626 × 10^−34 J·s.

Now, you can calculate the threshold frequency using the given values and the formula above.