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August 29, 2014

August 29, 2014

Posted by **Ashley** on Wednesday, November 28, 2012 at 6:50pm.

f(x)= 7- 2^x, [0,4], c=?

- Calculus -
**Steve**, Wednesday, November 28, 2012 at 7:03pmf(4) = -9

f(0) = 6

so, we want f'(c) = -15/4

f'(x) = -ln2 2^x

-15/4 = -ln2 2^c

15/(4ln2) = 2^c

ln(15/ln16) = c ln2

c = ln(15/(4ln2))/ln2 = 2.4356

which is in the interval [0,4]

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