Posted by Ashley on Wednesday, November 28, 2012 at 6:48pm.
∫2^x + 8 dx = 1/ln2 2^x + 8x
so, using the limits, we have
(2^5/ln2 + 40) - (2^0/ln2 + 0)
= 32/ln2 + 40 - 1/ln2
= 31/ln2 + 40
you are correct.
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