Posted by Ashley on Wednesday, November 28, 2012 at 6:48pm.
∫2^x + 8 dx = 1/ln2 2^x + 8x so, using the limits, we have (2^5/ln2 + 40) - (2^0/ln2 + 0) = 32/ln2 + 40 - 1/ln2 = 31/ln2 + 40 you are correct.