Posted by Erick on Wednesday, November 28, 2012 at 2:24pm.
1. What is the area of triangle ABC if a = 47.0°, β = 57.8°, and a = 10.2 cm?
A. 58.2 cm2
B. 43.5 cm2
C. 38.4 cm2
D. 33.3 cm2
2. Given triangle ABC with β = 41°, g = 14°, and a = 5.0, find the value of c.
A. 6.2
B. 4.0
C. 1.5
D. 17
3. Resolve the vector, v, with magnitude 2.0 × 102 and angle 60°.
A. v = 170i + 100j
B. v = 120i + 160j
C. v = 100i + 170j
D. v = 10i + 17j
4. What is the area of triangle ABC if a = 83.4 ft, b = 53.1 ft, and c = 37.2 ft?
A. 16,100 ft2
B. 709 ft2
C. 1,220 ft2
D. 76.0 ft2
5. Which of the following statements relating to the Pythagorean theorem are true?
(i) The magnitude of a vector is based on the Pythagorean theorem.
(ii) The law of cosines is based on the Pythagorean theorem.
(iii) The law of sines is based on the Pythagorean theorem.
A. (i) and (ii)
B. (i) only
C. (ii) only
D. (ii) and (iii)
6. How much work is done by raising a 117lb box vertically 18.0 inches?
A. 25,300 ftlb
B. 2,110 ftlb
C. 176 ftlb
D. 5,190 ftlb
7. Given triangle ABC with g = 61.0°, β = 29.0°, and b = 20.5, find the value of a.
A. 37.0
B. 11.4
C. 42.3
D. 9.94
8. Given triangle ABC with b = 14.0, c = 11.0, and β = 105°, find the value of a.
A. 20
B. 8.7 and 20
C. 6.3
D. 6.3 and 12

Math  Steve, Wednesday, November 28, 2012 at 3:20pm
#1
using c as the base, the altitude is a sinβ
since we have α and β, γ = 75.2°
c/sinγ = a/sinα, so
c = 1.2/sin47.0° sin75.2° = 1.59
area = 1/2 base*height = 1/2 * 1.59 * 10.2 * sin57.8° = 6.86 cm^2
how far do you get on the others?

Math  Steve, Wednesday, November 28, 2012 at 3:23pm
Oops I see I dropped a 0. Picking up in the middle,
c = 10.2/sin47.0° sin75.2° = 13.48
area = 1/2 base*height = 1/2 * 13.48 * 10.2 * sin57.8° = 58.17 cm^2

Math  Erick, Thursday, November 29, 2012 at 11:54pm
can you please do them all? pleaseeeeeee
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