Shasha
posted by Help STEVE! on .
What is the exact value of sin(2 theta) if cos (theta)=3/5 and (theta) is in quadrent 4?
12/25
24/25
12/25
7/25
24/25

sin2θ = 2sinθcosθ
in QIV, if cosθ = 3/5, sinθ = 4/5
so, sin2θ = 2(4/5)(3/5) = 24/25