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December 21, 2014

December 21, 2014

Posted by **Mary** on Wednesday, November 28, 2012 at 7:45am.

A cardinal (Richmondena cardinalis) of mass 4.50×10^−2 kg and a baseball of mass 0.142 kg have the same kinetic energy. What is the ratio of the cardinal's magnitude p(c) of momentum to the magnitude p(b) of the baseball's momentum?

Part B:

A man weighing 650 N and a woman weighing 460 N have the same momentum. What is the ratio of the man's kinetic energy K(m) to that of the woman K(w)?

- PHYSICS - PLEASE HELP -
**Henry**, Friday, November 30, 2012 at 7:38pmA. 0.5Mc*Vc^2 = 0.5Mb*Vb^2.

0.5*0.045*Vc^2 = 0.5*0.142*Vb^2

0.0225(Vc)^2 = 0.071(Vb)^2

Vc^2 = 3.156Vb^2.

Vc = 1.77Vb

Mc*Vc/Mb*Vb

Replace Vc with 1.77Vb:

Mc*1.77Vb/Mb*Vb

0.045*1.77Vb/(0.142*Vb

0.07965Vb/0.142Vb = 0.561 = Momentum of

Cardinal/Momentum of baseball.

B. m1*g = 650 N.

m1=650/g=650/9.8 = 66.3 kg.=Mass of man

m2*g = 460 N.

m2=460/9.8 = 46.94 kg. = Mass of woman.

m1*V1 = m2*V2.

66.3V1 = 46.9V2

V2 = 1.414V1.

K1/K2 = 0.5m1*V1^2/0.5m2*V2^2

K1/K2 = 0.5*66.3*V1^2/0.5*46.9*V2^2

K1/K2 = 33.15V1^2/23.45V2^2

Replace V2 with 1.414V1:

K1/K2 = 33.15V1^2/23.45*(1.414V1)^2

K1/K2 = 33.15V1^2/46.9V1^2 = 0.707.

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