3 points particles with masses 4kg,2kg,3kg are at the corners of equilateral triangle of side m =2m.

To find the gravitational potential energy of the system, we can use the formula:

๐‘ƒ๐ธ = โˆ’๐บ ร— ๐‘š1 ร— ๐‘š2 รท ๐‘Ÿ

Where:
๐‘ƒ๐ธ is the gravitational potential energy
๐บ is the gravitational constant (approximately 6.674 ร— 10^-11 N m^2/kg^2)
๐‘š1 and ๐‘š2 are the masses of the particles
๐‘Ÿ is the distance between the particles

Since the triangle is equilateral, all sides are of equal length. Let's consider side "m", which is 2 meters long.

Now, to calculate the gravitational potential energy between two particles, we need to find the distance between them. In an equilateral triangle, the distance between any two particles can be expressed as a fraction of the side length "m".

Let's label the particles as A, B, and C. The distance between A and B is "dAB", the distance between B and C is "dBC", and the distance between C and A is "dCA".

From the properties of an equilateral triangle, we know that the height of the triangle (from any corner to the midpoint of the opposite side) is โˆš3/2 times the side length. Therefore, the height of the triangle is (โˆš3/2) ร— 2 = โˆš3 meters.

To calculate the distances between the particles, we can use the Pythagorean theorem. Since the height of the equilateral triangle bisects the base, we have two right-angled triangles.

In triangle ABC, with A being the top vertex and BC being the base:
- The height of the triangle (โˆš3 meters) is the opposite side.
- Half of BC (which is m/2 = 2/2 = 1 meter) is the adjacent side.

Using the Pythagorean theorem, we can calculate the distance between particles A and B:

dAB^2 = (1 meter)^2 + (โˆš3 meters)^2
dAB^2 = 1 meter^2 + 3 meters^2
dAB^2 = 1 + 3
dAB^2 = 4

Therefore, dAB = โˆš4 = 2 meters.

Similarly, we can find the distances dBC and dCA.
dBC = 2 meters
dCA = 2 meters

Now that we have the distances between the particles, we can calculate the gravitational potential energy for each pair of particles:

For particles A and B:
๐‘ƒ๐ธAB = โˆ’๐บ ร— 4 kg ร— 2 kg รท 2 meters

For particles B and C:
๐‘ƒ๐ธBC = โˆ’๐บ ร— 2 kg ร— 3 kg รท 2 meters

For particles C and A:
๐‘ƒ๐ธCA = โˆ’๐บ ร— 3 kg ร— 4 kg รท 2 meters

Finally, to find the total gravitational potential energy of the system, we sum up the potential energies between all pairs of particles:

๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘ƒ๐ธ = ๐‘ƒ๐ธAB + ๐‘ƒ๐ธBC + ๐‘ƒ๐ธCA

which gives:

๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘ƒ๐ธ = (โˆ’๐บ ร— 4 kg ร— 2 kg รท 2 meters) + (โˆ’๐บ ร— 2 kg ร— 3 kg รท 2 meters) + (โˆ’๐บ ร— 3 kg ร— 4 kg รท 2 meters)

Simplifying this equation will give you the numerical value for the total gravitational potential energy of the system.