Post a New Question

calculus

posted by on .

Find the point (x,y) on the curve y=sqrt(x+4) closest to the origin.

  • calculus - ,

    The distance from a point on the line from the origin is

    ((y-0)^2 + (x-0)^2)^0.5 =

    (x^2+y^2)^.5 = (x^2 +(x+4)^0.5)

    evaluate d/dx((x^2 +(x+4)^0.5)) = 0

    This is the x value of the point closest to the origin, plug x into y = sqrt(x+4) to find the y value of this point

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question