a saturated solution of barium chloride at 30 degrees Celsius contains 150 g water. how much addition barium chloride ca be dissolved by heating this solution to 60 degrees celsius?

bacl2 at 30 degrees= 38.2
bacl2 at 60 degrees= 46.6

You didn't type everything. 150 g in what volume.

solubility BaCl2 @ 30 C = 38.2g/?gram H2O or volume H2O
Etc.

To determine how much additional barium chloride (BaCl2) can be dissolved by heating the saturated solution from 30 degrees Celsius to 60 degrees Celsius, we can use the concept of solubility.

Solubility is the amount of solute (in this case, BaCl2) that can dissolve in a given amount of solvent (in this case, water) at a specific temperature.

Given data:
- Saturated solution at 30 degrees Celsius contains 150 g of water.
- The solubility of BaCl2 at 30 degrees Celsius is 38.2.

To find out the maximum amount of BaCl2 that can be dissolved at 60 degrees Celsius, we need to compare the solubility at both temperatures.

Temperature Change:
- Increase from 30 degrees Celsius to 60 degrees Celsius.

Solubility Change:
- BaCl2 at 30 degrees Celsius = 38.2
- BaCl2 at 60 degrees Celsius = 46.6

Now, we can calculate the difference in solubility between 60 and 30 degrees Celsius (Δsolubility):

Δsolubility = Solubility at 60 degrees Celsius - Solubility at 30 degrees Celsius
Δsolubility = 46.6 - 38.2
Δsolubility = 8.4

Therefore, the difference in solubility between 60 and 30 degrees Celsius is 8.4.

To find the amount of additional BaCl2 that can be dissolved, we need to consider the amount of water in the saturated solution at 30 degrees Celsius.

Ratio of solubility to water:
- 38.2 g BaCl2 dissolves in 150 g water at 30 degrees Celsius.

Now, we can set up a proportion to find the additional BaCl2 that can be dissolved when the solution is heated to 60 degrees Celsius:

(Δsolubility)/(solubility at 30 degrees Celsius) = (additional BaCl2)/(amount of water)

Using the proportion:

(8.4)/(38.2) = (additional BaCl2)/(150)

Now, we can solve for the additional BaCl2:

8.4 * 150 = 38.2 * (additional BaCl2)
1260 = 38.2 * (additional BaCl2)

Additional BaCl2 = 1260 / 38.2
Additional BaCl2 ≈ 32.98 g

Therefore, by heating the saturated solution of BaCl2 at 30 degrees Celsius to 60 degrees Celsius, approximately 32.98 g of additional BaCl2 can be dissolved.